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what is the value of t? $t-23^\\circ$ $t-12^\\circ$ $t+48^\\circ$ $t = …

Question

what is the value of t?
$t-23^\circ$
$t-12^\circ$
$t+48^\circ$
$t = \square^\circ$
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Explanation:

Step1: Use exterior angle property

The exterior angle of a triangle equals the sum of the two non-adjacent interior angles. So:
$t+48^\circ=(t-23^\circ)+(t-12^\circ)$

Step2: Simplify right-hand side

Combine like terms on the right:
$t+48^\circ=2t-35^\circ$

Step3: Isolate variable $t$

Subtract $t$ and add $35^\circ$ to both sides:
$48^\circ+35^\circ=2t-t$
$83^\circ=t$

Answer:

Explanation

Step1: Use exterior angle property

The exterior angle of a triangle equals the sum of the two non-adjacent interior angles. So:
$t+48^\circ=(t-23^\circ)+(t-12^\circ)$

Step2: Simplify right-hand side

Combine like terms on the right:
$t+48^\circ=2t-35^\circ$

Step3: Isolate variable $t$

Subtract $t$ and add $35^\circ$ to both sides:
$48^\circ+35^\circ=2t-t$
$83^\circ=t$

Answer

$t=83^\circ$