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Aufgabe

Lösungsschritte

1. Understand the question

   Turn 1 Question

   order of operations
   1） 4×(2×3 + 6²) - 6
   2） (10 + 4)² + (6 - 18 ÷ 2)
   3） (8 +26 - 2) ÷ 2 + 6²
   4） 6×(13×3 + 5²) +10
   5） (14 +45 - 3²) ÷( 10 - 5)
   6） (11 +26 - 5) ÷ 4 - 7²
   7） (11 +34 - 3²) ÷(-3 + 7)
   8） (7 + 4)² + (13 - 16 ÷ 4)
   9） (16 - 4) × (12 + 3) + 7²
   10） (19 + 6) × (10 + 6) - 9²

   Turn 2 Question

   Give me the correct answer for each problem

   Turn 3 Question

   Whats 11 to the power of 2

   Turn 4 Question

   7 to the power of 2

2. Response

   Turn 1 Answer

   Let's solve problem 2: \((10 + 4)^2 + (6 - 18 \div 2)\) using the order of operations (PEMDAS/BODMAS).

3. Explanation

   Step 1: Simplify parentheses (brackets)

   First, handle the operations inside the parentheses. For \((10 + 4)\), we add 10 and 4. For \((6 - 18 \div 2)\), we perform the division first (since division comes before subtraction in PEMDAS), then the subtraction.

   • For \((10 + 4)\): \(10 + 4 = 14\)
   • For \((6 - 18 \div 2)\): First, \(18 \div 2 = 9\), then \(6 - 9 = -3\)

   Now the expression becomes \(14^2 + (-3)\)

   Step 2: Simplify exponents

   Next, we handle the exponent. \(14^2 = 14 \times 14 = 196\)

   Now the expression is \(196 + (-3)\)

   Step 3: Perform addition (and subtraction, which is adding a negative)

   \(196 + (-3) = 196 - 3 = 193\)

4. Final answer

   \(193\)

   Turn 2 Answer

   Got it, let's go through each one step by step using PEMDAS/BODMAS:

   1. \(4 \times (2 \times 3 + 6^2) - 6\)

   • Inside parentheses: \(2×3=6\), \(6²=36\), so \(6+36=42\)
   • Then: \(4×42=168\), \(168-6=162\)

   Correct answer: 162

   1. \((10 + 4)^2 + (6 - 18 \div 2)\)

   • First parentheses: \(10+4=14\), \(14²=196\)
   • Second parentheses: \(18÷2=9\), \(6-9=-3\)
   • Then: \(196 + (-3)=193\)

   Correct answer: 193

   1. \((8 + 26 - 2) \div 2 + 6^2\)

   • Inside parentheses: \(8+26=34\), \(34-2=32\)
   • Then: \(32÷2=16\), \(6²=36\), \(16+36=52\)

   Correct answer: 52

   1. \(6 \times (13 \times 3 + 5^2) + 10\)

   • Inside parentheses: \(13×3=39\), \(5²=25\), \(39+25=64\)
   • Then: \(6×64=384\), \(384+10=394\)

   Correct answer: 394

   1. \((14 + 45 - 3^2) \div (10 - 5)\)

   • Top parentheses: \(3²=9\), \(14+45=59\), \(59-9=50\)
   • Bottom parentheses: \(10-5=5\)
   • Then: \(50÷5=10\)

   Correct answer: 10

   1. \((11 + 26 - 5) \div 4 - 7^2\)

   • Inside parentheses: \(11+26=37\), \(37-5=32\)
   • Then: \(32÷4=8\), \(7²=49\), \(8-49=-41\)

   Correct answer: -41

   1. \((11 + 34 - 3^2) \div (-3 + 7)\)

   • Top parentheses: \(3²=9\), \(11+34=45\), \(45-9=36\)
   • Bottom parentheses: \(-3+7=4\)
   • Then: \(36÷4=9\)

   Correct answer: 9

   1. \((7 + 4)^2 + (13 - 16 \div 4)\)

   • First parentheses: \(7+4=11\), \(11²=121\)
   • Second parentheses: \(16÷4=4\), \(13-4=9\)
   • Then: \(121+9=130\)

   Correct answer: 130

   1. \((16 - 4) \times (12 + 3) + 7^2\)

   • First parentheses: \(16-4=12\)
   • Second parentheses: \(12+3=15\)
   • Then: \(12×15=180\), \(7²=49\), \(180+49=229\)

   Correct answer: 229

   1. \((19 + 6) \times (10 + 6) - 9^2\)

   • First parentheses: \(19+6=25\)
   • Second parentheses: \(10+6=16\)
   • Then: \(25×16=400\), \(9²=81\), \(400-81=319\)

   Correct answer: 319

   Turn 3 Answer

   11 squared is 121! That's 11 multiplied by itself (11×11) 😊

   Turn 4 Answer

   7 squared is 49! That's 7 multiplied by itself (7×7) 😊

Antwort

Question Analysis

OCR Text

7 to the power of 2

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