$\\overline{pq}$ is reflected across the line $x=-3$. the coordinates o…
D. $(-8, 4)$
D. $(-8, 4)$
$\\overline{pq}$ is reflected across the line $x=-3$. the coordinates of the endpoints of the image of $\\overline{pq}$ are $p(5, 2)$ and $q(2, 4)$. what are the coordinates of $q$?
a $(1,4)$
b $(-3,4)$
c $(5,4)$
d $(-8,4)$
$\\overline{pq}$ is reflected across the line $x=-3$. the coordinates of the endpoints of the image of $\\overline{pq}$ are $p(5, 2)$ and $q(2, 4)$. what are the coordinates of $q$?
a $(1,4)$
b $(-3,4)$
c $(5,4)$
d $(-8,4)$
For a point $(x,y)$ reflected over $x=k$, the pre-image $x$-coordinate satisfies $k = \frac{x + x'}{2}$, where $x'$ is the image $x$-coordinate. The $y$-coordinate stays the same.
We have $k=-3$, $x'=2$, $y'=4$.
Rearrange the formula: $x = 2k - x'$
Substitute values: $x = 2(-3) - 2 = -6 - 2 = -8$
Since reflection over vertical line preserves $y$-coordinate, $y = y' = 4$.
D. $(-8, 4)$
For a point $(x,y)$ reflected over $x=k$, the pre-image $x$-coordinate satisfies $k = \frac{x + x'}{2}$, where $x'$ is the image $x$-coordinate. The $y$-coordinate stays the same.
We have $k=-3$, $x'=2$, $y'=4$.
Rearrange the formula: $x = 2k - x'$
Substitute values: $x = 2(-3) - 2 = -6 - 2 = -8$
Since reflection over vertical line preserves $y$-coordinate, $y = y' = 4$.
D. $(-8, 4)$
$\\overline{pq}$ is reflected across the line $x=-3$. the coordinates of the endpoints of the image of $\\overline{pq}$ are $p(5, 2)$ and $q(2, 4)$. what are the coordinates of $q$?
a $(1,4)$
b $(-3,4)$
c $(5,4)$
d $(-8,4)$
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
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Their sides or their angles
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