question 1-6 in $\\triangle jkl$, $m\\angle l = 90^\\circ$. if $\\sin j…
\( 0.6 \)
\( 0.6 \)
question 1-6
in $\\triangle jkl$, $m\\angle l = 90^\\circ$. if $\\sin j = 0.6$, what is the value of $\\cos k$ to the nearest tenth?
enter the correct answer in the box.
question 1-6
in $\\triangle jkl$, $m\\angle l = 90^\\circ$. if $\\sin j = 0.6$, what is the value of $\\cos k$ to the nearest tenth?
enter the correct answer in the box.
In right triangle \( \triangle JKL \) with \( \angle L = 90^\circ \), the sum of the other two angles \( \angle J \) and \( \angle K \) is \( 90^\circ \) (since the sum of angles in a triangle is \( 180^\circ \), and \( \angle L = 90^\circ \)). So \( \angle J + \angle K = 90^\circ \), which means \( \angle K = 90^\circ - \angle J \).
We know the co - function identity \( \cos(90^\circ - \theta)=\sin\theta \). Let \( \theta=\angle J \), then \( \cos K=\cos(90^\circ - \angle J) \). By the co - function identity, \( \cos(90^\circ - \angle J)=\sin\angle J \).
We are given that \( \sin J = 0.6 \). Since \( \cos K=\sin J \), then \( \cos K = 0.6 \).
\( 0.6 \)
In right triangle \( \triangle JKL \) with \( \angle L = 90^\circ \), the sum of the other two angles \( \angle J \) and \( \angle K \) is \( 90^\circ \) (since the sum of angles in a triangle is \( 180^\circ \), and \( \angle L = 90^\circ \)). So \( \angle J + \angle K = 90^\circ \), which means \( \angle K = 90^\circ - \angle J \).
We know the co - function identity \( \cos(90^\circ - \theta)=\sin\theta \). Let \( \theta=\angle J \), then \( \cos K=\cos(90^\circ - \angle J) \). By the co - function identity, \( \cos(90^\circ - \angle J)=\sin\angle J \).
We are given that \( \sin J = 0.6 \). Since \( \cos K=\sin J \), then \( \cos K = 0.6 \).
\( 0.6 \)
question 1-6 in $\\triangle jkl$, $m\\angle l = 90^\\circ$. if $\\sin j = 0.6$, what is the value of $\\cos k$ to the nearest tenth? enter the correct answer in the box.
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
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\( 42.5 \)
\( 0.8 \)
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