a population of geese has two color phenotypes, brown and gray. color is controlled by a single gene, with the brown allele dominant. a random sample of 250 geese finds that 210 are brown. what percentage of geese are heterozygous? (assume that the population is in hardy - weinberg equilibrium.) multiple choice 36% 48% 64% 57% 43%

Question

Accepted Answer

# Explanation:
## Step1: Calculate gray geese count
$250 - 210 = 40$
## Step2: Find recessive genotype frequency
$q^2 = \frac{40}{250} = 0.16$
## Step3: Solve for recessive allele freq.
$q = \sqrt{0.16} = 0.4$
## Step4: Solve for dominant allele freq.
$p = 1 - 0.4 = 0.6$
## Step5: Calculate heterozygote frequency
$2pq = 2 	imes 0.6 	imes 0.4 = 0.48$
## Step6: Convert to percentage
$0.48 	imes 100 = 48\%$
# Answer:
48%

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QUESTION IMAGE

Question

Explanation:

Step1: Calculate gray geese count

Step2: Find recessive genotype frequency

Step3: Solve for recessive allele freq.

Step4: Solve for dominant allele freq.

Step5: Calculate heterozygote frequency

Step6: Convert to percentage

Answer: