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题目

解题步骤

1. Understand the question
   1. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is 9.8 m/s², how much work is done against gravity?

   a. 10 j
   b. 20 j
   c. 49 j
   d. 98 j

2. Explanation

   Step1: Recall the formula for work done against gravity

   The work done against gravity is given by the formula \( W = mgh \), where \( m \) is the mass, \( g \) is the acceleration due to gravity, and \( h \) is the height.

   Step2: Substitute the given values into the formula

   We are given \( m = 5.0 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), and \( h = 2.0 \, \text{m} \). Plugging these values into the formula:
   \( W = 5.0 \times 9.8 \times 2.0 \)
   First, calculate \( 5.0 \times 9.8 = 49 \), then multiply by \( 2.0 \): \( 49 \times 2.0 = 98 \, \text{J} \)

3. Final answer

   D. 98 J

答案

Question Analysis

OCR Text

3. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is 9.8 m/s², how much work is done against gravity?

a. 10 j
b. 20 j
c. 49 j
d. 98 j

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