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If point (3,-5) is on the graph of f(x) what point must be on the graph…

1. First blank: y-axis 2. Second blank: x-values 3. Third blank: y-values Filled sentence: Horizontal transformations reflect a function over the **y-axis**. Thus, they transform …

Kategorie: calculus Aktualisiert: 2026-02-03

Aufgabe

Turn 1 Question

to review functions and their transformations, complete the following activity. drag and drop the words into the correct locations. horizontal transformations reflect a function over the. thus, they transform a given function $y = f(x)$ to $y = f(-x)$. to reflect a given function horizontally, multiply all by $-1$ while keeping the the same. $y$-values $x$-axis $y$-axis $x$-values

Turn 2 Question

If the funtionnis f (x) =x3 complete thr table for its horizontal f election

Turn 3 Question

The table has x on top then 0,1,2 then under that js f(-x) then 3 blank box’s HELO fill thoes in

Turn 4 Question

The parabola rises and falls in a quadrant 4. The curve passes through left parentheses 0.4 comma negative 5 right parentheses left parentheses 1 comma negative 2 right parentheses peak at vertex left parentheses 2 comma 0 right parentheses descends through left parentheses 3 comma negative 2 right parentheses and left parentheses 3.6 comma negative 5 right parentheses all values are approximate. The table shows x -1, -2, -3 and under is f(-x) then 3 blank boxes help me fill thoes in

Turn 5 Question

F(x)=(x+1)2 and the function of it’s horizontal reflection whag js the potion of the point (-4,9) in the reflected funtin the (-4,9) reflects to blank in f(-x)

Turn 6 Question

If point (3,-5) is on the graph of f(x) what point must be on the graph of f(-x)

Lösungsschritte

  1. Understand the question
    Turn 1 Question

    to review functions and their transformations, complete the following activity. drag and drop the words into the correct locations. horizontal transformations reflect a function over the. thus, they transform a given function $y = f(x)$ to $y = f(-x)$. to reflect a given function horizontally, multiply all by $-1$ while keeping the the same. $y$-values $x$-axis $y$-axis $x$-values

    Turn 2 Question

    If the funtionnis f (x) =x3 complete thr table for its horizontal f election

    Turn 3 Question

    The table has x on top then 0,1,2 then under that js f(-x) then 3 blank box’s HELO fill thoes in

    Turn 4 Question

    The parabola rises and falls in a quadrant 4. The curve passes through left parentheses 0.4 comma negative 5 right parentheses left parentheses 1 comma negative 2 right parentheses peak at vertex left parentheses 2 comma 0 right parentheses descends through left parentheses 3 comma negative 2 right parentheses and left parentheses 3.6 comma negative 5 right parentheses all values are approximate. The table shows x -1, -2, -3 and under is f(-x) then 3 blank boxes help me fill thoes in

    Turn 5 Question

    F(x)=(x+1)2 and the function of it’s horizontal reflection whag js the potion of the point (-4,9) in the reflected funtin the (-4,9) reflects to blank in f(-x)

    Turn 6 Question

    If point (3,-5) is on the graph of f(x) what point must be on the graph of f(-x)

  2. Response
    Turn 1 Answer
  3. Brief Explanations
    1. Horizontal reflection of a function $y=f(x)$ to $y=f(-x)$ is a flip over the y-axis.
    2. This transformation modifies the input values (x-values) by multiplying them by -1, leaving the output values (y-values) unchanged.
  4. Final answer
    1. First blank: y-axis
    2. Second blank: x-values
    3. Third blank: y-values

    Filled sentence:
    Horizontal transformations reflect a function over the y-axis. Thus, they transform a given function $y = f(x)$ to $y = f(-x)$. To reflect a given function horizontally, multiply all x-values by $-1$ while keeping the y-values the same.

    Turn 2 Answer

    Got it! First, let's remember that the horizontal reflection of \( f(x) = x^3 \) is \( g(x) = f(-x) = (-x)^3 = -x^3 \).

    Let me make a sample table with common x-values to show both the original and reflected function values:

    | x | Original \( f(x) = x^3 \) | Reflected \( g(x) = -x^3 \) |
    |----|---------------------------|------------------------------|
    | -2 | \( (-2)^3 = -8 \) | \( -(-2)^3 = 8 \) |
    | -1 | \( (-1)^3 = -1 \) | \( -(-1)^3 = 1 \) |
    | 0 | \( 0^3 = 0 \) | \( -0^3 = 0 \) |
    | 1 | \( 1^3 = 1 \) | \( -1^3 = -1 \) |
    | 2 | \( 2^3 = 8 \) | \( -2^3 = -8 \) |

    See how each reflected y-value is just the opposite of the original? That’s the horizontal flip over the y-axis doing its thing. Did you have specific x-values you needed to fill in, or is this enough? 😊

    Turn 3 Answer

    Got you, let's fill those in quick!

    Since the original function is \( f(x) = x^3 \), the horizontal reflection is \( f(-x) = (-x)^3 \). Let's calculate each one:

    • When x = 0: \( f(-0) = (-0)^3 = 0 \)
    • When x = 1: \( f(-1) = (-1)^3 = -1 \)
    • When x = 2: \( f(-2) = (-2)^3 = -8 \)

    So the blanks under f(-x) are 0, -1, -8 in order! 😎

    Turn 4 Answer

    Got it, let's work through this step by step!

    First, remember that f(-x) means we take each given x-value, flip its sign, then find the corresponding y-value from the parabola's points you described.

    Let's go one by one:

    1. When x = -1: We calculate -x = -(-1) = 1. Looking at your parabola, when x=1, the y-value is -2. So f(-1) = -2
    2. When x = -2: -x = -(-2) = 2. The vertex is at (2, 0), so the y-value here is 0. So f(-2) = 0
    3. When x = -3: -x = -(-3) = 3. Your parabola passes through (3, -2), so the y-value is -2. So f(-3) = -2

    To recap, the blanks (in order for x=-1, -2, -3) are: -2, 0, -2

    Turn 5 Answer

    Got it, let's break this down simply!

    First, the horizontal reflection of \( F(x) = (x+1)^2 \) is \( F(-x) = (-x + 1)^2 \).

    Now, to find where the…

Antwort

Response

Turn 1 Answer

Brief Explanations

  1. Horizontal reflection of a function $y=f(x)$ to $y=f(-x)$ is a flip over the y-axis.
  2. This transformation modifies the input values (x-values) by multiplying them by -1, leaving the output values (y-values) unchanged.

Answer

  1. First blank: y-axis
  2. Second blank: x-values
  3. Third blank: y-values

Filled sentence:
Horizontal transformations reflect a function over the y-axis. Thus, they transform a given function $y = f(x)$ to $y = f(-x)$. To reflect a given function horizontally, multiply all x-values by $-1$ while keeping the y-values the same.

Turn 2 Answer

Got it! First, let's remember that the horizontal reflection of \( f(x) = x^3 \) is \( g(x) = f(-x) = (-x)^3 = -x^3 \).

Let me make a sample table with common x-values to show both the original and reflected function values:

| x | Original \( f(x) = x^3 \) | Reflected \( g(x) = -x^3 \) |
|----|---------------------------|------------------------------|
| -2 | \( (-2)^3 = -8 \) | \( -(-2)^3 = 8 \) |
| -1 | \( (-1)^3 = -1 \) | \( -(-1)^3 = 1 \) |
| 0 | \( 0^3 = 0 \) | \( -0^3 = 0 \) |
| 1 | \( 1^3 = 1 \) | \( -1^3 = -1 \) |
| 2 | \( 2^3 = 8 \) | \( -2^3 = -8 \) |

See how each reflected y-value is just the opposite of the original? That’s the horizontal flip over the y-axis doing its thing. Did you have specific x-values you needed to fill in, or is this enough? 😊

Turn 3 Answer

Got you, let's fill those in quick!

Since the original function is \( f(x) = x^3 \), the horizontal reflection is \( f(-x) = (-x)^3 \). Let's calculate each one:

  • When x = 0: \( f(-0) = (-0)^3 = 0 \)
  • When x = 1: \( f(-1) = (-1)^3 = -1 \)
  • When x = 2: \( f(-2) = (-2)^3 = -8 \)

So the blanks under f(-x) are 0, -1, -8 in order! 😎

Turn 4 Answer

Got it, let's work through this step by step!

First, remember that f(-x) means we take each given x-value, flip its sign, then find the corresponding y-value from the parabola's points you described.

Let's go one by one:

  1. When x = -1: We calculate -x = -(-1) = 1. Looking at your parabola, when x=1, the y-value is -2. So f(-1) = -2
  2. When x = -2: -x = -(-2) = 2. The vertex is at (2, 0), so the y-value here is 0. So f(-2) = 0
  3. When x = -3: -x = -(-3) = 3. Your parabola passes through (3, -2), so the y-value is -2. So f(-3) = -2

To recap, the blanks (in order for x=-1, -2, -3) are: -2, 0, -2

Turn 5 Answer

Got it, let's break this down simply!

First, the horizontal reflection of \( F(x) = (x+1)^2 \) is \( F(-x) = (-x + 1)^2 \).

Now, to find where the point (-4, 9) maps to on the reflected function:
When we do a horizontal reflection, we flip the sign of the original x-value (because we're replacing x with -x in the function). The y-value stays the same, since horizontal transformations don't affect the output.

Original x-coordinate: -4 → flipped x-coordinate is -(-4) = 4
Original y-coordinate: 9 → stays 9

Wait, let's double-check by plugging in to confirm: \( F(-4) = (-4 + 1)^2 = (-3)^2 = 9 \) (that's the original point). For the reflected function, plug x=4: \( F(-4) \) is the original, but the reflected function at x=4 is \( F(-(4)) = F(-4) = 9 \). Yep, that matches.

So (-4, 9) reflects to (4, 9) in \( f(-x) \)!

Turn 6 Answer

Got it, let's figure this out! A horizontal reflection (which is what f(-x) is) flips the x-coordinate's sign but keeps the y-coordinate the same.

Since (3, -5) is on f(x), we just flip the x-value from 3 to -3, and leave y as -5. So the point on f(-x) is (-3, -5)! 😊

Question Analysis

Subject mathematics
Sub Subject calculus
Education Level high school
Difficulty unspecified
Question Type text only
Multi Question Yes
Question Count 6
Analysis Status completed
Analyzed At 2026-02-03T21:05:36

OCR Text

Show OCR extraction
If point (3,-5) is on the graph of f(x) what point must be on the graph of f(-x)

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