find the vertex of the parabola ( y = x^2 ). simplify both coordinates …
\((0, 0)\)
\((0, 0)\)
find the vertex of the parabola ( y = x^2 ). simplify both coordinates and write them as proper fractions, improper fractions, or integers. ( , ) submit
find the vertex of the parabola ( y = x^2 ). simplify both coordinates and write them as proper fractions, improper fractions, or integers. ( , ) submit
The vertex form of a parabola is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.
The given equation is \( y = x^2 \). We can rewrite it as \( y = 1(x - 0)^2 + 0 \).
By comparing with the vertex form \( y = a(x - h)^2 + k \), we can see that \( h = 0 \) and \( k = 0 \).
\((0, 0)\)
The vertex form of a parabola is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.
The given equation is \( y = x^2 \). We can rewrite it as \( y = 1(x - 0)^2 + 0 \).
By comparing with the vertex form \( y = a(x - h)^2 + k \), we can see that \( h = 0 \) and \( k = 0 \).
\((0, 0)\)
find the vertex of the parabola ( y = x^2 ). simplify both coordinates and write them as proper fractions, improper fractions, or integers. ( , ) submit
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
| Equation | Solution (Fraction) | Solution (Decimal) | |----------|---------------------|--------------------| | $2x=3$ | $\frac{3}{2}$ | $1.5$ | | $5y=3$ | $\frac{3}{5}$ | $0.6$…
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\(-15\)
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s (for each sub - problem): 1. Through \((3,-5)\), parallel to \(y = 5x-3\): \(y = 5x-20\) 2. Through \((1,5)\), parallel to \(y = 5x-4\): \(y = 5x\) 3. Through \((-2,4)\), parall…
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